RUS
24-02-2008, 13:58
Привет!
Может у кого будет время помочь со следующими задачами по электроники.. ПАРНИ ОЧЕНЬ НУЖНО..... Спасибо
1) ele1.png
1.a) Find the value for Rb so, that the control signal will drive transistor T1 into saturation (=totally ON) although may have any value between 100...250. Rload is 200 ohms. (2 points)
1.b) Find the power that is consumed in the transistor T1 and in the Rload as T1 is fully conducting. (2 points)
2) ele2.png
Let R1=1kohm and R2=100kohms and C2=38pF. Investigate, what is the main reason for the high frequency restriction of the following circuit, so that it cannot be used for amplifying signals above certain frequencies. Find the highest useful frequency and the reason for that.
The input signal can be as large as 200mVpp.
The opamp is listed to have SR=0,3 V/us and fT=1,1 MHz. (max score 5 points)
3) ele3.png
Calculate the worst case DC-error-voltage at the output of the following circuit as it is known, that the specific opamp has Ib+ = 100 nA and Ib- = 90 nA. The databook provides the following value: Voffs = 2 mV. R3=200 kohms and R1=1kohms and R2=100kohms. (max score 5 points)
(vsig=100mVpp @ 0...100 Hz)
Может у кого будет время помочь со следующими задачами по электроники.. ПАРНИ ОЧЕНЬ НУЖНО..... Спасибо
1) ele1.png
1.a) Find the value for Rb so, that the control signal will drive transistor T1 into saturation (=totally ON) although may have any value between 100...250. Rload is 200 ohms. (2 points)
1.b) Find the power that is consumed in the transistor T1 and in the Rload as T1 is fully conducting. (2 points)
2) ele2.png
Let R1=1kohm and R2=100kohms and C2=38pF. Investigate, what is the main reason for the high frequency restriction of the following circuit, so that it cannot be used for amplifying signals above certain frequencies. Find the highest useful frequency and the reason for that.
The input signal can be as large as 200mVpp.
The opamp is listed to have SR=0,3 V/us and fT=1,1 MHz. (max score 5 points)
3) ele3.png
Calculate the worst case DC-error-voltage at the output of the following circuit as it is known, that the specific opamp has Ib+ = 100 nA and Ib- = 90 nA. The databook provides the following value: Voffs = 2 mV. R3=200 kohms and R1=1kohms and R2=100kohms. (max score 5 points)
(vsig=100mVpp @ 0...100 Hz)